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This question is about quadratic equations. The question asks which of the following quadratic equations has a sum of its roots as 4.
In general, for a quadratic equation of the form ax^2 + bx + c = 0, the sum of the roots is represented by -b/a.
Let’s analyze the answer choices one by one:
(a) 2x^2 – 4x + 8 = 0
If we were to solve this equation, we would find that the sum of the roots is -(-4)/2 = 2.
Discard (a).
(b) -x^2 + 4x + 4 = 0
If we were to solve this equation, we would find that the sum of the roots is -4/(-1) = 4. This is the answer.
(c) √2x^2 – (4/√2)x + 1 = 0
If we were to solve this equation, we would find that the sum of the roots is -(-4/√2) / √2 = 2.
Discard (c).
(d) 4x^2 – 4x + 4 = 0
If we were to solve this equation, we would find that the sum of the roots is -(-4)/4 = 1.
Discard (d).
Therefore, the quadratic equation that has a sum of its roots as 4 is -x^2 + 4x + 4 = 0.
One response to “Which of the following quadratic equations has the sum of its roots as 4”
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